10v^2+25v-167=12

Solution for 10v^2+25v-167=12 equation:

10v^2+25v-167=12

We move all terms to the left:

10v^2+25v-167-(12)=0

We add all the numbers together, and all the variables

10v^2+25v-179=0

a = 10; b = 25; c = -179;
Δ = b2-4ac
Δ = 252-4·10·(-179)
Δ = 7785
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7785}=\sqrt{9*865}=\sqrt{9}*\sqrt{865}=3\sqrt{865}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-3\sqrt{865}}{2*10}=\frac{-25-3\sqrt{865}}{20}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+3\sqrt{865}}{2*10}=\frac{-25+3\sqrt{865}}{20}
$